Slitherlink by Takeya Saikachi – The Art of Puzzles


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Slitherlink by Takeya Saikachi

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or solve online (using our beta test of Penpa-Edit tools in edgex mode where left click+drag draws lines and right click marks X’s)

Theme: Similar Instances

Author/Opus: This is the 27th puzzle from our contributing puzzlemaster Takeya Saikachi.

Rules: Standard Slitherlink rules.

Difficulty: 2 stars

Time Standards (highlight to view): Grandmaster = 1:00, Master = 2:00, Expert = 4:00

Solution: To be posted on our next puzzle post once live.

Note: Follow this link for classic Slitherlink and this link for Slitherlink variations. If you are new to this puzzle type, here are our easiest Slitherlink puzzles to get started on. More Slitherlink puzzles can be found in The Art of Puzzles, Slitherlink and Variations, and our beginner-friendly book Logic Puzzles 101.

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TomTom by Thomas Snyder – The Art of Puzzles


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TomTom by Thomas Snyder

PDF

or solve online (using our beta test of Penpa-Edit tools)

Theme: Square Dance

Author/Opus: This is the 428th puzzle from Thomas Snyder, aka Dr. Sudoku.

Rules: Standard TomTom rules, using the integers 1-6.

Difficulty: 2 stars

Time Standards (highlight to view): Grandmaster = 1:40, Master = 2:30, Expert = 5:00

Solution: To be posted on our next puzzle post once live.

Note: Follow this link for classic TomTom and this link for TomTom variations. If you are new to this puzzle type, here are our easiest TomTom to get started on. More TomTom puzzles can be found in the TomTom collection, in The Art of Puzzles, and in our beginner-friendly collection Intro to GMPuzzles by Serkan Yürekli.

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Previous Solution: “Identical Pairs” Tapa by Serkan

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Heroine REM Overview | Mantastic Puzzle and Dragons

Introduction

The Heroine event returns once again to North America and comes with a myriad of buffs for nearly every single card. Unfortunately, this event still costs 10 Magic Stones and the vast majority of the bottom rarity cards feel grossly outdated despite the buffs.

In fact, even the 6-star cards have questionable value with the vast majority of meaningful cards residing in the top rarity. While they do feature a healthy 17.5% chance of being rolled, they can simply be Monster Exchanged for if you feel they will greatly improve your Monster Box.

On the bright side, all cards feature Weapon Assists along with the option to pull five times at once. This multi-pull feature will grant players 5 random rewards but at the same time, will cost 50 Magic Stones and I do not truly feel this is a great place to spend your precious Stones.

As a

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Nanro (Tapa) by JinHoo Ahn – The Art of Puzzles


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Nanro (Tapa) by JinHoo Ahn

PDF

or solve online (using our beta test of Penpa-Edit tools; use the tab key to alternate between shading and number entry modes)

Theme: Four by Four

Author/Opus: This is the 64th puzzle from our contributing puzzlemaster JinHoo Ahn.

Rules: Variation of Nanro rules with Tapa clue elements: Label some cells with numbers to form a single connected group of labeled cells; no 2×2 group of cells may be fully labeled. Each bold region must contain at least one labeled cell. Each number must equal the total count of labeled cells in that region. Numbers in a gray cell indicate the length of consecutive labeled cells in its neighbors. If there is more than one number in a gray cell, then there must be at least one

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Nanro Loop by Bryce Herdt – The Art of Puzzles


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Nanro by Bryce Herdt

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or solve online (using our beta test of Penpa-Edit tools; use the tab key to alternate between shading, number entry, and composite loop drawing modes)

Theme: Parquet

Author/Opus: This is the 23rd puzzle from guest contributor Bryce Herdt.

Rules: Variation of Nanro rules. Label some cells with numbers to form a single non-intersecting loop; no 2×2 group of cells may be fully labeled, but the loop may touch itself orthogonally or diagonally. The region boundaries divide the loop into segments, and each region must have at least one segment. Numbers denote the length in cells of each segment within a region; all numbers in a region must be the same. When two numbers from different segments are orthogonally adjacent, the numbers must be different. (Consequently, segments

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